Tuesday, January 30, 2018

Simplifying Algebraic Expressions

Read the following problems and solve by simplifying the expressions.  
1.  A string of length g inches is cut into two pieces.  One piece is 10 inches longer than the other.  Find the length of the shorter piece.  


2.  Kenny has m guppies and 10 angelfish.  He buys another 20 guppies and 30 angelfish.  How many fish does Kenny have now?


3.   8 + 12s - 7 - 9s + 4




Comment below to answer one or all questions.  Make sure to identify the problem you are solving.  I will not display your answers until tomorrow afternoon.  



5.0A.1  I can use parentheses, brackets, or braces in numerical (and algebraic) expressions, and evaluate with these symbols.  
5.OA.2  I can write simple expressions that record calculations with numbers, and interpret numerical (and algebraic) expressions without evaluating them. 

18 comments:

  1. 1. The shorter piece is (g-10).
    2. Kenny has (m+20+40) fish in all.
    3. (3s+5)

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  2. For number three I got 5+3s.

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  3. I chose to solve number 3. The answer is - 5 + 3s.

    I also solved number 2 and I got - 60 + m.

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  4. For number 3 I got 5+3s

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  5. 2. 60 + m
    3. 5 + 3s
    1. g/2 + 10

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  6. 3. 5 + 3s
    2. 60 + m
    1. g / 2 + 10

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  7. 1. g/2+10 2. m+60 3. 5+3s

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  8. #3. =3s+5
    #2. he has 60+m fish.

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  9. Answers:
    1. g/2 - 10
    2. m+60
    3. 5+3s

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  10. 1. ? 2. Kenny has m+60 fish. 3. 5+3s

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  11. The answer to Problem No. 3 is 5+3s.

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  12. 3. 8 + 12s - 7 - 9s + 4 = 21s + 5
    2. Kenny has m guppies and 10 angelfish. He buys another 20 guppies and 30 angelfish. How many fish does Kenny have now? = 20m +40
    1. A string of length g inches is cut into two pieces. One piece is 10 inches longer than the other. Find the length of the shorter piece. = 2g x 11



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  13. The answer to number one is g/2 add 10.

    The answer for number two is Kenny has m +20 +10 +30 fish in all

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  14. 1.
    2. Kenny has m+60 fish now.
    3. 5 + 3s

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  15. answer #1=g/5
    answer #2=m+60
    answer #3=5+3s

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